Tension, length, and sag of stay ropes.
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Tension, length, and sag of stay ropes.

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Published by The Institution in London .
Written in English

Subjects:

  • Rope

Book details:

Edition Notes

StatementBy Charles George Watson.
SeriesThe Institution of Civil Engineers. Selected engineering papers ..., no. 136
Classifications
LC ClassificationsTS1785 .W3
The Physical Object
Pagination28 p.
Number of Pages28
ID Numbers
Open LibraryOL6445442M
LC Control Number42042954
OCLC/WorldCa6758714

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You can't pull a piece of string perfectly straight - you just can't see the sag. (excluding the limit where variations in the thickness of the string are greater than the sag) Two simple ways of looking at it: Mathematically - As you pull tighter the sag gets less, but it's a function of 1/force, so to get zero sag you need infinite force.   1) The basic catenary tension/sag equation is T = wl^2/ (8*d) Actually, that is not the equation of a catenary. It assumes a parabolic drape, but it is probably close enough for your purposes. Start with the desired sag, d and calculate T (cable) for the non-iced condition. Estimate d for the added weight of ice. Calculate T (ice), deflection. Captain Van der Hum. A Piratical Tale in two ropes' length, for male voices, book and lyrics by M. E. Inch. Vocal Score by Herbert, William Rhys and a great selection of related books, art and collectibles available now at   In a longer rope the weight has to be supported also. It is the same principle you see when power wires sag between poles. If the ends of the rope are to be completely horizontal, then a lot of tension has to be applied to counteract the weight. If the ends of the rope are allowed to pivot, then the tension does not have to be as great.

  The inch diameter steel wire weighs about pounds per foot. So for a 10 foot span between level supports, and 30 pounds tension at a given temperature, the sag at the low point (mid point of the span) is d=wl^2/8T = feet, or about 3/ of an inch. For a foot span with that same tension, d = wl^2/8T = feet (about 3.   If you don’t have a tension gauge, consider purchasing one after you read Product Review: Loos Tension Gauge. Tighten the adjuster just enough to take the slack out of the backstay and so that it won’t interfere with the boom when the mainsail is raised. This will be the minimum backstay tension setting. DESIGN OF TENSION MEMBERS Version II The tension members can have a variety of cross sections. The single angle and double angle sections [Fig 2(a)] are used in light roof trusses as in industrial buildings. The tension members in bridge trusses are made of channels or I sections, acting individually or built-up [Figs. 2(c) and 2(d)].File Size: KB.   D = length of sagging rope L/2 = meters The Attempt at a Solution So, because the rope is being pulled with a tension of 55 N to keep the object at a certain distance, the tension throughout the string with the mass is 55 N. I made theta my angle with the horizontal, which is the value i'm trying to find.

  This book on wire ropes is dedicated mainly to all users of wire ropes – the construction engineers, operators and supervisors of machines and instal- tions running on wire ropes – and it is divided into three main sections. The?rst section deals with the di?erent types of wire rope and their component parts, the second looks into the e?ects of wire ropes under . Tension is the intermolecular force that exists inside of ropes and strings and other kind of materials that you can pull on but that also are flexible. So here's the idea the purpose of tension is to maintain the integrity of the string or the rope. No stretchy no breaky, okay same length and it's not going to break. Tension in a string is a scalar quantity (i.e. non-negative). Zero tension is slack. A string or rope is often idealized as one dimension, having length but being massless with zero cross there are no bends in the string, as occur with vibrations or pulleys, then tension is a constant along the string, equal to the magnitude of the forces applied by the ends of the string.   3. Tune the mast from the top shroud on-down, making sure the mast is in column. Remember: as you tension one shroud by adjusting the turnbuckle, to loosen the opposing shroud the same amount. Image courtesy of Berthon Marina, UK. Click image to link to their site. 4. Once the mast is fairly straight from side to side, tighten the shrouds all.